# Please answer me the question attached from Suarez root over 2 over Suare root over 2 for 24 times

LET         $(\sqrt{2\sqrt{2\sqrt{2}}})$X24 TIMES=K
$\Rightarrow 2\sqrt{2\sqrt{2}}}$x24=kxk
$\Rightarrow (2\times 2^{1/2}\times 2^{1/2})\times 24=_k{2} \Rightarrow( 2\times 2)\times 24=k^{2} \Rightarrow4\times 24=k^{2} \Rightarrow 96=k^{2} \Rightarrow k=4\sqrt{6}$
HENCE,the value of the given above equation is $4\sqrt{6}$