In a triangle ABC, AD is median to side BC. Angle BDA=45 degree and CAD = 30 degree. Then find angle BAD.
In a triangle ABC, AD is median to side BC. Angle BDA=45 degree and CAD = 30 degree. Then find angle BAD.
abcd , 9 Years ago
Grade 9
9 grade maths> In a triangle ABC, AD is median to side B...
1 AnswersSarah Saha
Last Activity: 9 Years ago
Given angle BDA=45 degree &angle CAD=30 degree
Now ,In tri.ADC,angle ADC =(180-45)=135 degree & angles (ADC+CAD+ACD)=180 degree
From this,we get angle ACD=15 degree.
Now,BD=CD,i.e BC=2CD i.e angle BAC=2CAD i.e angle BAC=2x30=60
Therefore;angle BAD=(BAC-CAD)=60-30=30 degree
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