In a triangle ABC, AB=AC and angle A = 50, find angle B and angle C

Triangle ABC is an isosceles triangle because the two sides are equal that is AB=AC
Angle A =50
So in isosceles triangle the angles opposite to equal sides are equal
So Angle B=Angle C
Then Angle C can be written as Angle B
now by angle sum property
A+B+C=180
A+B+B=180
A+2B=180
50+2B=180
2B=180-50
2B=130
B=130/2
B=65
So Angle C =65
Therefore Angle B=65 and Angle C=65