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Grade 99 grade maths

HELLO SIR OR MADAM,

MY DOUBT IS-

1) SIMPLYFY - (83a15b)1/6 × (4a2b2)1/3

Profile image of Ashwin Satheesh
11 Years agoGrade 9
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1 Answer

Profile image of SHAIK AASIF AHAMED
ApprovedApproved Tutor Answer11 Years ago
Hello student,
Please find the answer to your question below
Given =(83a15b)1/6(4a2b2)1/3
Equalising powers of both expressions by squaring and appling square root
we get=(83a15b)1/6(16a4b4)1/6
=(8192 a19b5)1/6
=(4096 a18b6)1/6(2 a/b)1/6
= 4a3b\sqrt[6]{2a/b}