Find three consecutive odd numbers whose sum is 219.

Let's solve the problem step by step.

We are asked to find three consecutive odd numbers whose sum is 219.

Let the three consecutive odd numbers be:

The first odd number = x
The second odd number = x + 2 (since odd numbers differ by 2)
The third odd number = x + 4 (again, consecutive odd numbers differ by 2)
The sum of these three numbers is given as 219, so we can set up the equation:

x + (x + 2) + (x + 4) = 219

Now, combine like terms:

3x + 6 = 219

Next, subtract 6 from both sides of the equation to isolate the term with x:

3x = 219 - 6 3x = 213

Now, divide both sides of the equation by 3 to solve for x:

x = 213 / 3 x = 71

Now that we know x, the three consecutive odd numbers are:

The first number = 71
The second number = 71 + 2 = 73
The third number = 71 + 4 = 75
Therefore, the three consecutive odd numbers are 71, 73, and 75.

Finally, let's check if their sum is indeed 219:

71 + 73 + 75 = 219

So, the three consecutive odd numbers whose sum is 219 are 71, 73, and 75.