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Grade: 9
        
Could someone tell me how to solve this problem (attached)?
one month ago

Answers : (2)

Arun
22974 Points
							
then assume a/ b = t (for simplicity in writing)
(t^3 + 2t)/ (2t^2 + 1) = 123/136
Now cross multiply and solve for t which is obviouslya/b
one month ago
Vikas TU
9468 Points
							
Dear stuent 
136 t^3 + 272t^2 = 246t^2 + 123 
136 t^3 + 26t^2 -123 = 0 
Solve this the ans would be 
x1 = 0.90735
x2 = -0.54927 + i * 0.83371
x3 = -0.54927 - i * 0.83371
 
So , a/b = 9/10
Hope this help 
one month ago
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