c, t and v are curved surface area , total surface area and volume of a cylinder then show that: th 2 = ch square + 4 v square + 8v square × rh where r and h are radius and height

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Arun · Answer

Take rhs of this question Th^2=Ch^2+ 4V^2 +8 V^2 r h CSA of cylinder= 2πrh TSA of cylinder =2πr(r+h) Vol. Of cylinder = π r^2 h Now take RHS :- 2πrh× (h^2) + 4 (πr^2h)^2 + 8 (πr^2h)^2 × r × h = 2π × r × h^3 + 4 ×π^2 × r^4 × h^2 + 8 π^2 r^5 × h^3

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c, t and v are curved surface area , total surface area and volume of a cylinder then show that: th 2 = ch square + 4 v square + 8v square × rh where r and h are radius and height

c, t and v are curved surface area , total surface area and volume of a cylinder then show that: th^{2 = ch square + 4 v square + 8v square × rh where r and h are radius and height}

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c, t and v are curved surface area , total surface area and volume of a cylinder then show that: th 2 = ch square + 4 v square + 8v square × rh where r and h are radius and height

c, t and v are curved surface area , total surface area and volume of a cylinder then show that: th2 = ch square + 4 v square + 8v square × rh where r and h are radius and height

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c, t and v are curved surface area , total surface area and volume of a cylinder then show that: th^{2 = ch square + 4 v square + 8v square × rh where r and h are radius and height}