To calculate the volume of ice cream in the cone, we first need to calculate the full volume of the cone and then account for the fact that \(\dfrac{1}{6}\) of it is unfilled.
### Step 1: Volume of the cone
The formula for the volume \(V\) of a cone is given by:
\[
V = \dfrac{1}{3} \pi r^2 h
\]
Where:
- \(r\) is the radius of the base of the cone = 5 cm
- \(h\) is the height of the cone = 10 cm
- \(\pi\) is approximately 3.1416
Substitute the values into the formula:
\[
V = \dfrac{1}{3} \times 3.1416 \times 5^2 \times 10
\]
\[
V = \dfrac{1}{3} \times 3.1416 \times 25 \times 10
\]
\[
V = \dfrac{1}{3} \times 3.1416 \times 250
\]
\[
V = \dfrac{1}{3} \times 785.4
\]
\[
V = 261.8 \, \text{cm}^3
\]
### Step 2: Volume of the ice cream
Since \(\dfrac{1}{6}\) of the cone is unfilled, the ice cream fills \(\dfrac{5}{6}\) of the cone's volume.
\[
\text{Volume of ice cream} = \dfrac{5}{6} \times 261.8
\]
\[
\text{Volume of ice cream} = 218.17 \, \text{cm}^3
\]
Rounding to the nearest integer:
\[
\text{Volume of ice cream} \approx 218 \, \text{cm}^3
\]
Thus, the volume of the ice cream is approximately **218 cm³**.
