Pawan Prajapati
Last Activity: 3 Years ago
Ci) 8a3 + b8 + 12.a2b + 6ab2
= (2a)3 + (b>3 + S(2a)(bX2a + b)
= (2a + bi3
[Using identity: x3 + y3 + aty(x + y) = + y)3]
= (2a + b)(2a + b)(2a + b).
(i) aaa -ba - 12a2b + 6ab2
= (2a>3 -(b'/3 - 3(2a)2b + 3(2a>b2
= (2a - b'f
[Using identity: x3 - y8 - :U2y + 3%y2 = ex - y)3]
= (2a - b)(2a - b)(2a - b).
(iii') 27 - 125a8 - l36a + 225a2
= (3)3 - C6a>3 - 3 x C3>2 x (6a)+ 3(3X5a>2
"" (3 - 5a>3
[Using identity: x3 - y8 - 3% + 3%y2 = ex - y )8]
"" (3 - 6a)(3 - fla)(3 - 5a).
(iv) 64a3 - 27b3 - 144a2b + 108ab2
= (4a)3 - (3bl3 - 3(4af(3b) + 3(4a)(3b>2
= (4a - 3b)3
[Using identity: r.3 -y8 - 3% + azy2 = (.r _ y)3]
= (4a '."" 3bX4a - 3b)(4a - 3b).
(v) 27pa - _1_ - p2 + != (3p"I - ( a- 3 x (3p)2
IB 2 4 6 .
)( + 3 )( (3p) x (J
42
= (Sp-)8
[Using identity: -:i -3% + 3x.>'2 = (% - Y)8]