Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

5 boya and 3 girls seated in a row.find the probability that all girl sits alternate?

5 boya and 3 girls seated in a row.find the probability that all girl sits alternate?

Grade:12th pass

2 Answers

Vaibhav
50 Points
4 years ago
First arrange boys by factorial 5 ways now as □ □ □ □ □ as shown in arrangements there will be 6 blank space then arrange girls by 6C3 ways final answer will be (factorial5 ×6C3)÷factorial8
Piyush Kumar Behera
436 Points
4 years ago
@vaibhav
the above solution is completely wrong,this is for those questions  which give condition that no 2 girls are sitting together,but it is given that all girls are sitting alternate.
for this do the following.Arrange the girls in alternate position    G    G    G  and the girls can be arranged in 3! ways among themselves..
THEN THE FOLLOWING CASES ARE POSSIBLE
B  B  B  G  B  G  B  G  --- girls can be arranged in 3!xboys be arranged in 5! ways
B  B  G  B  G  B  G  B  --- girls can be arranged in 3!xboys be arranged in 5! ways
B  G  B  G  B  G  B  B  --- girls can be arranged in 3!xboys be arranged in 5! ways
G  B  G  B  G  B  B  B  --- girls can be arranged in 3!xboys be arranged in 5! ways
 
so probability= 4x3!x5!/8!=1/14

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free