3. In figure, if AB 11 DE, LBAC = 35° and LCDE = 53°, find LDCE. A DE

Question

Pawan Prajapati · Answer

AB II DE and AE is.transversal. .. LDEC = LBAC = 35° ...(i) Now, in triangle CDE, LCDE = 53° ...(ii) [Given] and LDCE + LDEC + LCDE = 180° [Sum of angles of a triangle is 180°.] ::) LDCE +.35° + 53° = 180° [From (i) and (ii)] ::) LDCE = 180° - 88° = 92°.

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3. In figure, if AB 11 DE, LBAC = 35° and LCDE = 53°, find LDCE. A DE

3. In figure, if AB 11 DE, LBAC = 35° and LCDE = 53°, find LDCE.

A

DE

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