2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that
Ci) AD bisects BC (U) AD bisects LA

Question

2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that Ci) AD bisects BC (U) AD bisects LA

Pawan Prajapati · Answer

Consider triangles ABD and ACD, We have AB = AC [Given] AD = AD [Common] LADB = LADC [90° each] MBD :::: MCD [RHS rule) .LDhc (i) .• BD = CD [CPCT] AD bisects BC. (ii) and LBAD = LCAD AD bisects LBAC, i.e., LA

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2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that Ci) AD bisects BC (U) AD bisects LA

2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that
Ci) AD bisects BC (U) AD bisects LA

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2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that Ci) AD bisects BC (U) AD bisects LA

2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that Ci) AD bisects BC (U) AD bisects LA

1 Answers

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2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that
Ci) AD bisects BC (U) AD bisects LA