if the 2 sides of a triangle and the included angles r a=1+3^1/2 cm, b = 2 cm C = 60^0. solve the

triangle.

Dear

a=1+3^1/2 cm, b = 2 cm C = 60⁰

use cos formula

cos60 = (b² + a² -c²) /2ba

put the value

c= √6

now

  c/sinC = b /sinB

B=45

so A = 180-60-45

       =75

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