And from the first equation,
cos (A + 2B) = cos A. cos 2B – sin A.sin 2B
∴ A+2B=π2,3π2 …(iii)
Given that < A < π/2 and 0 < B < π/2
⇒ 0<A+2B<3π2 …(iv)
∴ From (iii) and (iv),
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B.Tech, IIT Delhi