Grade upto college level Integral Calculus
Please check my answer and tell me where I am wrong? The answer according to the answer key for thi question is 2
0∫pi/2(1+sin x)1/2dx = 0∫pi/2(sin x/2 + cos x/2)dx = [-2cos x/2 + 2sin x/2]0pi/2 = -2cos pi/4 + 2sin pi/4 = -√2 + √2 = 0
Please check my answer and tell me where I am wrong? The answer according to the answer key for thi question is 2
0∫pi/2(1+sin x)1/2dx = 0∫pi/2(sin x/2 + cos x/2)dx = [-2cos x/2 + 2sin x/2]0pi/2 = -2cos pi/4 + 2sin pi/4 = -√2 + √2 = 0
