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Grade 10Inorganic Chemistry

calculate the ph of 0.05 M sulphuric acid when it is fully dissociated.

Profile image of aritra nandy
15 Years agoGrade 10
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2 Answers

Profile image of AKASH GOYAL AskiitiansExpert-IITD
15 Years ago

Dear Aritra

H2SO4 -> 2H+ + SO4-2

0.05M will give 0.1 M of H+

pH=-log[H+]=-log0.1=1

All the best.

AKASH GOYAL

AskiitiansExpert-IITD

 

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Profile image of vikas askiitian expert
15 Years ago

H2SO4 = 2H+ + SO42-

 0.05M H2SO4 gives 2(0.05)M H+

 [H+] = 0.1

-log[H+] = PH =1

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