Grade 11General Physics

A monkey of mass 20 Kg is holding a vertical rope. The rope can break when a mass of 25 Kg is suspended

from it. What is the maximum acceleration with which the monkey can climb up along the rope?

(a)2.5 ms-2 (b) 5 ms-2 (c) 7 ms-2 (d) 10 ms-2

jeet jeetu

13 Years agoGrade 11

8 Answers

Anirban Mukherjee

Approved Tutor Answer13 Years ago

Let the monkey climb up with acceleration a. Then tension caused in the rope will be T =

M(g+a), where M is the mass of the monkey. Maximum value of T is 25g = 20(g + a). Taking

g = 10ms

-2, it gives a = 2.5 ms

Aman Bansal

13 Years ago

Dear Jeet,

assuming the value of g is 10ms^-2, the maximum weight that the rope can hold is

25 k g \times 10 N k g - 1 = 250 N

. (though it should be less than 250, I''m not so sure about the maimum part) using F=ma,

a = 250 N 20 k g = 12.5 m s - 2

The maximum acceleration of the monkey is 12.5ms^-2

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somy chaturvedi

13 Years ago

tension is responsiblefor upward acc. and maximum tension it can bear is 250N. hence max acc.

250-200=20*a

a=2.5m/s^2

sheik arbaz

13 Years ago

2.5 m/s-2

Shahvar Tyagi

9 Years ago

A monkey of mass 20 kg. is holding a vertical rope. The rope will not break when a mass of 25 kg. is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration it which the monkey can climb up along the rope

Ajinkya kawale

9 Years ago

let the initial tension be Tusing fbd for m=20kg we get,T-mg=maT-20g=20a…1Tmax-25g=0Tmax=25g……2from 1,225g-20g=20a5g=20aa=g/4 =2.5m/s^2hope this helps…

Vicky Singh

7 Years ago

1kgf = 1kg * 10m/s square

=10N

For 25kgf=25kg * 10m/s square

=250N _____(1)

Monkey mass =20kg so mg=200N (2)

Subtract equation 2 from 1 we get

250N-200N=50N

Force = Mass *acceleration

50 =20kg * a

a = 2.5 m/s square

Rishi Sharma

5 Years ago

Dear Student,
Please find below the solution to your problem.

1kgf = 1kg * 10m/s square
=10N
For 25kgf=25kg * 10m/s square
=250N _____(1)
Monkey mass =20kg so mg=200N (2)
Subtract equation 2 from 1 we get
250N-200N=50N
Force = Mass *acceleration
50 =20kg * a
a = 2.5 m/s square

Thanks and Regards