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General Physics

At the surface of the earth, the time period of a pendulum is T1 and at a height of distance K above earth's surface is T2, then T1/T2=?

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Profile image of Arvind Petkar
15 Years agoGrade
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2 Answers

Profile image of Chetan Mandayam Nayakar
15 Years ago

T is inversely proportional to sqrt(g) therefore it is directly proportional to distance from centre of earth(for points on or above earth's surface). g=GM/R2      T1/T2 =(R/(R+K)) R is radius of earth

 

Profile image of Amitabh Shrivastava
15 Years ago

T is proportional to 1/[(g)^1/2]

t1/t2=[g'/g]^1/2

g=GM/R^2

g'=GM/(R+K)^2

t1/t2=[R/(R+K)]