MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Fawz Naim Grade:
        

An observer sees a flower pot sail up and then back down past a window 2.45 m high. If the total time the pot is in the sight is 1 s, what is the height above the window upto which the pot rises ?


 

6 years ago

Answers : (1)

AJIT AskiitiansExpert-IITD
68 Points
										

Dear  Fawz naim ,


THe time the pot takes to go up and down through the window must be same as the conditions in both cases are same. The magnitude of velocity at the entry and exit points are same and distance travelled is same too . so time taken to go up and down = 0.5 s


now we can take the axis of reference anywhere on the trajectory of the motion , we take it on the bottom of window. Assuming the velociyt at that point to be u , and applying the equaitons of motion ,


2.45 = u*(.5) -(1/2) *9.8*.52


solving we get u = 7.35m/s


so the maximum height from the bottom of the window = u2/2g  = 2.7625


height from the top of window is  2.7625- 2.45 = .306 m


 


Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.


All the best.


Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.


Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..


Askiitians Expert


Ajit Singh Verma IITD


 

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
  • Kinematics & Rotational Motion
  • OFFERED PRICE: R 600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details