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```        7. A boy throws a table tennis ball of mass 20 g upwards with a velocity of u 0 = 10 m/s at an angle q 0 with
the vertical. The wind imparts a horizontal force of 0.08 N, so that the ball returns to the starting point.
Then, the angle q 0 must be such that, tan q 0 is
(A) 0.2 (B) 0.4 (C) 2.5 (D) 1.2```
7 years ago

419 Points
```										Dear Deepak
see the pic for the solution
All the best.
AKASH GOYAL

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```
7 years ago
510 Points
```										for verticle motion
Uy = U0COS@   &   ay = -g
applying  VY = UY + ayt
Vy at topmost point is zero so
t= uy/g
tim of flight (T)= 2t=2Uy/g .........1
for horizontal motion
Ux = UOCOS@
Sx = UxT + axT2
finally particle reaches to same point so displacement  is zero ..
0 = UxT + axT2/2    .........2
putting value of T in eq 2
Uy/Ux = g/a  .........3
max = force =0.08
ax = 4m/s2
now , UY/UX = Uocos@/Uosin@
=tan@=10/4=2.5
option c is correct

```
7 years ago
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