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`        a point charge q is located on axis of disc of radius r at distance b from the plane of disc.if one-fourth of electric flux from charge passes through disc then.......(a)r = b    (b)r = 2b`
7 years ago

147 Points
```										Dear Dinesh
Draw a sphere whose center is at a distance b from the disk and which cover the disk

we know that flux throug a segment which makes an angel  θ at the center is
Φ=Q/2ε (1-cosθ)

where cosθ = b/(b2+r2)1/2
given flux passes in 1/4 th
so Q/2ε (1-cosθ)  =Q/4ε
1-cosθ = 1/2
cosθ =1/2
b/(b2+r2)1/2 =1/2
r =√3 b
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin

```
7 years ago
Nitish Sainani
24 Points
```										(it is disk not the spherical cap how can you take a sphere)

```
one year ago
Carelle
13 Points
```										A 1000w laser beam is concentrated by a Lens of a cross-sectional area of 10^-5 cm^2 . find the corresponding amplitude of the electric field
```
2 months ago
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