Force of attraction between two co axial short electric dipoles

We know that, Coulomb force, F = Kq₁q₂/d²
Dipole moment, p =qd.
So, q₁= p₁/d and q₂= p₂/d
Putting these values in Coulomb force, we get,
F = K(p₁/d) (p₂/d)/d²
= K (p₁) (p₂)/d⁴
Therefore, Force is varies fourth power of distance.

hello students


We know that, Coulomb force, F = Kq1q2/d2 Dipole moment, p =qd. So, q1= p1/d and q2= p2/d Putting these values in Coulomb force, we get, F = K(p1/d) (p2/d)/d^2 = K (p1) (p2)/d^4 Therefore, Force is varies fourth power of distance.

Hope it helps
Thankyou

Dear Students

We know that, Coulomb force, F = Kq₁q₂/d²
Dipole moment, p = qd.
So, q₁= p₁/d and q₂ = p₂/d
Putting these values in Coulomb force, we get,
F = K(p₁/d) (p₂/d)/d²
= K (p₁) (p₂)/d⁴
Therefore, It is clearly seen that Force varies with fourth power of distance.

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya