+91-87964 74404
FlagBACK
Question icon
Grade 11Electrostatics

The work of electric field done during the displacement of a negatively charged particle towards a fixed positively charged particle is 9J. As a result the distance between the charges has been decreased by half. What work is done by the electric field over the first half of this distance?

Ans: 3J

How we are getting this answer plz explain

Profile image of venkata sreekanth
14 Years agoGrade 11
Answers icon

1 Answer

Profile image of arpan chandrashekhar
14 Years ago

given:

kQq/(x/2) - kQq/x =9 where x is the intial distance.  . . . 

or kQq/x = 9J

to find is

KQq/(3/4*x) - kQq/x .... as the rdistance b/w the particles becomes 3/4*x as the particle approches by a quater*x

therefore it is kQq/3x =9/3 =3

Other Related Questions on electrostatics

question mark
Electrostatics question based on earthing of spherical shell
electrostatics
1 Answer Available

Last Activity: 3 Years ago

question mark
an object has a charge of 2c and gains 10^19 electrons. the net chaarge on the object becomes??
electrostatics
1 Answer Available

Last Activity: 4 Years ago

question mark
A wire with a linear charge density lambda forms a quarter of a cjrclenof radius R and is placed asa shown in thefigure with its centre of curvature at the origin O the electric field at O will be
electrostatics
1 Answer Available

Last Activity: 4 Years ago

question mark
Find the value of q so that system remains in equilibrium.. figure attached below
electrostatics
1 Answer Available

Last Activity: 4 Years ago

question mark
Need to find the time taken for the dipole to come back to eqm
 
electrostatics
1 Answer Available

Last Activity: 4 Years ago