3 equal 1.2*10^(-6) point charges placed at the corners of an equallatiral triangle with sides 0.5 m long.What is the elecntial tric potential energy of the system ?

let the vertices of triangle are a,b,c ..

side of the triangle is d...

electric potential energy of system = Kq_aq_b/d +kq_aq_c/d +kq_bq_c/d

 q_a = q_b =q_c =q

so PE = 3kq² /d

        =3*9*10⁹ *(1.2*10^-6)² /0.5

        =7.76*10^-2 joule