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abhik chowdhury Grade: 11
        

prove:


limit (x) tends to 0 ((sinlog(1+x)/x))=1

6 years ago

Answers : (2)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Abhik


this is 0/0 form apply L hospital rule


differentiate wrt x


[coslog(1+x)]/(1+x)


put x=0


coslog1/1


cos0= 1


All the best.


AKASH GOYAL


AskiitiansExpert-IITD


 


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6 years ago
vikas askiitian expert
510 Points
										

lim x->0 sinlog(1+x)/x


 at x=0 ,  0/0 form comes so we can use L holpital rule


        differentiating numerator and denominator


after differentiating


limx->0 coslog(1+x) /1+x


        =coslog1/1


        =cos0=1


hence proved

6 years ago
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