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A die is thrown 6 times. Find the total number of possible outcomes containing at least on 5

[answer=6^6 - 5^6]

6 years ago


Answers : (2)


dear Student

No. of outcomes containing atleast one 5 = Total possible outcomes - No. of solutions having no 5

=6*6*6*6*6*6  -  5*5*5*5*5*5

for outcomes having no 5...there are only 5 possible options

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Askiitians Experts

6 years ago

can anyone give the answer please?

5 years ago

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