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A die is thrown 6 times. Find the total number of possible outcomes containing at least on 5
[answer=6^6 - 5^6]
dear Student
No. of outcomes containing atleast one 5 = Total possible outcomes - No. of solutions having no 5
=6*6*6*6*6*6 - 5*5*5*5*5*5
for outcomes having no 5...there are only 5 possible options
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can anyone give the answer please?
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