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5 indians and 5 american couples meet at aparty and shake hands. if no wife shakes hands with her own husband and no indian wife shakes hands with a male, then the no. of hand shakes that take place in the party is?

6 years ago


Answers : (2)


Dear jee

total possible hand shake =20C2

indian women shake hand with male =5C1 *10C1 =50  ways (it include hand shake with her husband also)

american women shake hand with their husband in 5 ways

so desired hand shake = 20C2 -50-5


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6 years ago
I did it this way and got 95 as the answer.
1 Indian male would shake hands with 5 American males so total no of handshakes between Indian and American males = 25 (5*5)
1 Indian female would shake hands with 5 American females , so number of handshakes = 25
1 American male would shake hands with 4 American females , so total = 20 (5*4)
1 American female would shake hands with 5 Indian males , so total = 25
(can u guys tell me where am i going wrong)
2 months ago

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