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jee king king Grade: 12

5 indians and 5 american couples meet at aparty and shake hands. if no wife shakes hands with her own husband and no indian wife shakes hands with a male, then the no. of hand shakes that take place in the party is?

8 years ago

Answers : (4)

Badiuddin askIITians.ismu Expert
147 Points

Dear jee

total possible hand shake =20C2

indian women shake hand with male =5C1 *10C1 =50  ways (it include hand shake with her husband also)

american women shake hand with their husband in 5 ways

so desired hand shake = 20C2 -50-5


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8 years ago
Shashwat Sinha
36 Points
I did it this way and got 95 as the answer.


1 Indian male would shake hands with 5 American males so total no of handshakes between Indian and American males = 25 (5*5)

1 Indian female would shake hands with 5 American females , so number of handshakes = 25

1 American male would shake hands with 4 American females , so total = 20 (5*4)

1 American female would shake hands with 5 Indian males , so total = 25

(can u guys tell me where am i going wrong)
one year ago
Vanshika bhalla
11 Points
										I havent counted hanshakes among indian women and american ones that indian women will shake hands with rest of 4 so total of 5 women will lead to 5*4=20 hamdshakes samr case with american women they will also lead to 20 both adding upto 40 and giving answer 95+40= 135 handshakes
one year ago
11 Points
20C2 (total handshakes) - THE NO OF HAND SHAKES OF INDIAN WOMEN WITH MALES i.e. 5C1 X 10C- 5(handshakes of american males with their own wife). which if finally equal to 10C2 – 5C1X10C1 – 
3 months ago
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