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root[log(logx)-log(4-logx)-log3]=f(x)
=>[log(logx)-log(4-logx)-log3] >_0
log(lox)-Log(4-logx)>_log3
using loga-logb =log[a/b] we get
log[{logx} / {4- logx} ]>_log3 taking antilog both sides
[logx /{4-logx}] >_3
logx >_ [12- 3 logx]
4logx>_12
logx>_3
x>_e cube
x€ [e^3,infinity)
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