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anurag singhal Grade:
        root[log(logx)-log(4-logx)-log3]=f(x) 

find domain
8 years ago

Answers : (1)

Vanya Saxena
18 Points
										

root[log(logx)-log(4-logx)-log3]=f(x)


 =>[log(logx)-log(4-logx)-log3] >_0


log(lox)-Log(4-logx)>_log3                 


                    using  loga-logb =log[a/b]  we get


 log[{logx} / {4- logx} ]>_log3                                   taking antilog both sides


[logx /{4-logx}] >_3


logx  >_ [12- 3 logx]


4logx>_12


logx>_3


x>_e cube


                                             x€ [e^3,infinity)


 

8 years ago
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