+91-87964 74404
FlagBACK
Question icon
Algebra

(1-p)-3 for |p| <1

Profile image of indira das
15 Years agoGrade
Answers icon

1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:
Hello Student,
Please find answer to your question below

|p| < 1
Taylor series expansion at p = 0
(1-p)^{-3} = 1+3p+6p^2+10p^3+15p^4+21p^5+O(p^6))
Series expansion at p = 1
(1-p)^{-3} = \frac{1}{(1-p)^3}
(1-p)^{-3} = \frac{-1}{(p-1)^3}
(1-p)^{-3} = \frac{-1}{p^3-3p^3+3p-1}

Other Related Questions on algebra

question mark
What is a binomial expression?
algebra
1 Answer Available

Last Activity: 2 Years ago

question mark
Can we divide two vectors? If this is possible then how?
algebra
1 Answer Available

Last Activity: 2 Years ago

question mark
How do you write “the product of 18 and q” as an algebraic expression?
algebra
1 Answer Available

Last Activity: 2 Years ago

question mark
दहावीच्या आय सी एस इ विद्यार्थ्यांनी पुढे काय करायला पाहिजे
algebra
1 Answer Available

Last Activity: 3 Years ago

question mark
Find the least number of square tiles by which the floor of a room of dimensions 16.58 m and 8.32 m can be covered completely. why HCF and not LCM as “least” keywor dis given?
algebra
1 Answer Available

Last Activity: 3 Years ago