Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
yogesh gandhi Grade: 12

1.tana & tanb are root of x2+px+q=0then value

sin2(a+b) + psin(a+b)cos(a+b) + qcos2(a+b)=


2.number of possible order pair (a,b) for which the inequality

a(cosx -1) + b2 =cos(ax+b2) - 1 hold ture for all x belong to real no.


7 years ago

Answers : (1)

AskIITianExpert Srijan.iitd
8 Points

1. use sum of the roots and product of the roots to obtain the value of  tan(a+b).

after u get the value of tan(a+b) convert the given expression in terms of tan(a+b) and tan2(a+b) by taking common the cosine term.

put the value of tan(a+b) and get the answer!!!!


2.this problem can be solved easily using the graphs.

draw graphs for the expressions on the right hand side and the left hand side and see the portions in which they intersect.

u dont even need to sove the points where they intersect  you just count the intervals .Thats the answer.

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details