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if p:q=2:3 and x:y=4:5 then value of 5px + 3qy:10px + 4qy is
Dear as
p:q=2:3
let p=2k then q=3k
x:y=4:5
lt x=4u then y= 5u
5px + 3qy=5 (2k)(4u)+3(3k)(5u)=85ku
10px+4qy=10(2k)(4u)+ 4(3k)(5u)=140ku
hence 5px + 3qy:10px + 4qy = 85ku/140ku = 17/28
ALL the BEst
Abhinav Batra
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