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as sa Grade:
        

if p:q=2:3 and x:y=4:5 then value of 5px + 3qy:10px + 4qy is

7 years ago

Answers : (1)

AskiitiansExpert Abhinav Batra
25 Points
										

Dear as


p:q=2:3


let p=2k then q=3k


x:y=4:5


lt x=4u then y= 5u


5px + 3qy=5 (2k)(4u)+3(3k)(5u)=85ku


10px+4qy=10(2k)(4u)+ 4(3k)(5u)=140ku


hence 5px + 3qy:10px + 4qy = 85ku/140ku = 17/28


 


ALL the BEst


Abhinav Batra

7 years ago
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