Revision Notes on Harmonic Progression and Harmonic Mean
Thus 1/H1 = 1/a + a–b/(n+1)ab,
1/H2 = 1/a + 2(a–n)/(n+1)ab,
……….. ……….
1/Hn = 1/a + n(a–b)/(n+1)ab.

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As the nth term of an A.P is given by an = a + (n-1)d, So the nth term of an H.P is given by 1/ [a + (n -1) d].
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If we have a set of weights w1, w2, …. , wn associated with the set of values x1, x2, …. , xn, then the weighted harmonic mean is defined as
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Questions on Harmonic Progression are generally solved by first converting them into those of Arithmetic Progression.
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If ‘a’ and ‘b’ are two positive real numbers then A.M x H.M = G.M2
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The relation between the three means is defined as A.M > G.M > H.M
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If we need to find three numbers in a H.P. then they should be assumed as 1/a–d, 1/a, 1/a+d
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Four convenient numbers in H.P. are 1/a–3d, 1/a–d, 1/a+d, 1/a+3d
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Five convenient numbers in H.P. are 1/a–2d, 1/a–d, 1/a, 1/a+d, 1/a+2d
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