Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Solved Examoles on General Organic Chemistry: Question:1, Arrange the following compounds in order of decreasing acidity: (IIT- JEE 2013) I > II > III > IV III > I > II > IV IV > III > I > II II > IV > I >III Answer: 2. Solution, Electron donating groups increase the acidity of phenol when present as substituent on the benzene ring while electron withdrawing groups decrease the acidity of phenol. Cl and NO2 are electron withdrawing groups while -CH3 and -OCH3 are electron donating groups. However, nitro undergoes resonance also which allows it to better stabilize the negative charge of the oxygen as compare to chlorine and thus acidic character of nitro phenol would be higher than that of chloro phenol. So, Nitrophenol is the most acidic compound here followed by chloro phenol. Hence, the correct option is 2. Question.2: Which of the given statement(s) about N, O, P and Q with respect to M is (are) correct? (IIT-JEE 2012) M and N are non–mirror image stereoisomers M and O are identical M and P are enantiomers M and Q are identical Answer: 1, 2, 3 Solution: Fischer Projections of the molecules: It is clear that M and N are non–mirror image stereoisomers. M and O are the same molecules i.e. Identical M and P are the non-superimposable mirror images of hence they are enantiomers. N and Q are identical M and Q are also are non–mirror image stereoisomers i.e diasteriomers. Hence 1, 2 and 3 are the correct statements. Question:3, The total number of cyclic isomers possible for a hydrocarbon with the molecular formula C4H6 is ( IIT-JEE 210) Solution: 5 cyclic isomers are possible for C4H6, possible. Click Here to Download
Question:1, Arrange the following compounds in order of decreasing acidity: (IIT- JEE 2013)
Answer: 2.
Solution, Electron donating groups increase the acidity of phenol when present as substituent on the benzene ring while electron withdrawing groups decrease the acidity of phenol.
Cl and NO2 are electron withdrawing groups while -CH3 and -OCH3 are electron donating groups.
However, nitro undergoes resonance also which allows it to better stabilize the negative charge of the oxygen as compare to chlorine and thus acidic character of nitro phenol would be higher than that of chloro phenol.
So, Nitrophenol is the most acidic compound here followed by chloro phenol.
Hence, the correct option is 2.
Question.2: Which of the given statement(s) about N, O, P and Q with respect to M is (are) correct? (IIT-JEE 2012)
Answer: 1, 2, 3
Solution: Fischer Projections of the molecules:
It is clear that
M and N are non–mirror image stereoisomers.
M and O are the same molecules i.e. Identical
M and P are the non-superimposable mirror images of hence they are enantiomers.
N and Q are identical
M and Q are also are non–mirror image stereoisomers i.e diasteriomers.
Hence 1, 2 and 3 are the correct statements.
Question:3, The total number of cyclic isomers possible for a hydrocarbon with the molecular formula C4H6 is
( IIT-JEE 210)
Solution: 5 cyclic isomers are possible for C4H6, possible. Click Here to Download
Signing up with Facebook allows you to connect with friends and classmates already using askIItians. It’s an easier way as well. “Relax, we won’t flood your facebook news feed!”
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
