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Question: 1 ) Among the following complexes (K-P) K3[Fe(CN)6] (K), [Co(NH3)6]Cl3 (L), Na3[Co(Oxalate)3] (M), [Ni(H2O)6]Cl2 (N), K2[Pt(CN)6] (O) and [Zn(H2O)6](NO3)2 (P). The diamagnetic complexes are (IIT JEE -2012)
1) K, L, M, N
2) K, M, O, P
3) L, M, O ,P
4) L, M ,N ,O
Answer: C
Solution:
Complex
MetalIon
system
Complex Spin
Electronic Configuration
No. of Unpaired electrons
Magnetic Property
K3[Fe(CN)6]
Fe(III)
d5
Low Spin
t2g5 eg0
1
Paramagnetic
[Co(NH3)6]Cl3
Co(III)
d6
t2g6 eg0
0
Diamagnetic
Na3[Co(Oxalate)3]
[Ni(H2O)6]Cl2
Ni(II)
d8
High Spin
t2g6 eg2
2
K2[Pt(CN)6]
Pt(IV)
[Zn(H2O)6](NO3)2
Zn(II)
d10
t2g6 eg4
Hence, the correct option is C.
Question: 2 ) As per IUPAC nomenclature, the name of the complex [Co(H2O)4(NH3)2]Cl3 is
1) Tetraaquadiaminecobalt (III) chloride.
2) Tetraaquadiamminecobalt (III) chloride.
3) Diaminetetraaquacobalt (III) chloride.
4) Diamminetetraaquacobalt (III) chloride. (IIT JEE -2012)
Answer: D
The compound contains 4 H2O ligand and 2 NH3 ligand. Both of these are neutral so there names
would be used as such without adding any prefix of suffix. i.e. aqua and ammine.
Acording to alphabetical order ammine would come before aqua.
So, the IUPAC name is Diamminetetraaquacobalt (III) chloride.
Hence, the correct option is d.
Question 3) Geometrical shapes of the complexes formed by the reaction of Ni2+ with Cl-, CN- and H2O, respectively are (IIT JEE 2011)
1) octahedral, tetrahedral and square planar.
2) tetrahedral, square planar and octahedral.
3) square planar, tetrahedral and octahedral.
4) octahedral, square planar and octahedral.
Answer: b
Solution
Metal Ion
Ligand
Geometry
Ni2+
Cl-
[NiCl4]2-
Tetrahedral
CN-
[Ni(CN)4]2-
Square Planar
H2O
[Ni(H2O)6]2+
Octahedral
Hence, the correct option is B.
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