Chapter 3: Rationalisation Exercise – 3.2
Question: 1
Rationalize the denominator of each of the following:

Solution:

For rationalizing the denominator, multiply both numerator and denominator with √5


For rationalizing the denominator, multiply both numerator and denominator with √5


For rationalizing the denominator, multiply both numerator and denominator with √12


For rationalizing the denominator, multiply both numerator and denominator with √3


For rationalizing the denominator, multiply both numerator and denominator with √2


For rationalizing the denominator, multiply both numerator and denominator with


For rationalizing the denominator, multiply both numerator and denominator with √5

Question: 2
Find the value to three places of decimals of each of the following. It is given that


Solution:
Given,


Rationalizing the denominator by multiplying both numerator and denominator with


Rationalizing the denominator by multiplying both numerator and denominator with √10


Rationalizing the denominator by multiplying both numerator and denominator with √2


Rationalizing the denominator by multiplying both numerator and denominator with √2



Rationalizing the denominator by multiplying both numerator and denominator with√5

Question: 3
Express each one of the following with rational denominator:

Solution:

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know,


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know,


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know,


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)

As we know, (a - b)2 = (a2 – 2 × a × b + b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a - b)2 = (a2 – 2 × a × b + b2)

Question: 4
Rationalize the denominator and simplify:

Solution:

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)

As we know, (a - b)2 = (a2 – 2 × a × b + b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

Question: 5
Simplify:

Solution:

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor
and the rationalizing factor

Now, (a + b)(a - b) = (a2 - b2)

As we know, (a - b)2 = (a2 – 2 × a × b + b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor
and the rationalizing factor

Now as we know, (a + b)(a - b)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor
and the rationalizing factor

Now as we know, (a + b)(a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor
the rationalizing factor
and the rationalizing factor


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor
the rationalizing factor
and the rationalizing factor

Since, (a + b) (a - b) = (a2 - b2)

Question: 6
In each of the following determine rational numbers a and b:

Solution:
Given,

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)

On comparing the rational and irrational parts of the above equation, we get, a = 2 and b = 1

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b)= (a2 - b2)

On comparing the rational and irrational parts of the above equation, we get, a = 3 and b = 2

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b) = (a2 - b2)

On comparing the rational and irrational parts of the above equation, we get,


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b)(a - b)= (a2 - b2)

On comparing the rational and irrational parts of the above equation, we get, a = -1 and b = 1

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)

On comparing the rational and irrational parts of the above equation, we get, a = 92 and b = 12

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)

On comparing the rational and irrational parts of the above equation, we get,

Question: 7
If x = 2+√3, find the value of

Solution:
Given, x = 2 + √3,
To find the value of
We have, x = 2 + √3,

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

Since, (a + b) (a - b) = (a2 - b2)

We know that, (a3 + b3) = (a + b)(a2 − ab + b2)

Putting the value of x+1x in the above equation, we get,

Question: 8
If x = 3+√8, find the value of

Solution:
Given, x = 3 + √8,

We have, x = 3 + √8,

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor


Since, (a + b) (a - b) = (a2 - b2)

Question: 9
Find the value of
it being given that √3 = 1.732 and √5 = 2.236.
Solution:
Given,

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor


Since, (a + b) (a - b) = (a2 - b2)

= 3(2.236 + 1.732) = 3(3.968) = 11.904
Question: 10
Find the values of each of the following correct to three places of decimals, it being given that


Solution:

Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

Since, (a + b) (a - b) = (a2 - b2)


Rationalizing the denominator by multiplying both numerator and denominator with the rationalizing factor

As we know, (a + b) (a - b) = (a2 - b2)

= 7 + 7.07 = 14.07
Question: 11
If
find the value of 4x3 + 2x2- 8x + 7.
Solution:
Given,
and given to find the value of 4x3 + 2x2 − 8x + 7
2x = √3 + 1
2x – 1 = √3
Now, squaring on both the sides, we get, (2x − 1)2 = 3
4x2 − 4x + 1 = 3
4x2 − 4x + 1 − 3 = 0
4x2 − 4x − 2 = 0
2x2 − 2x − 1 = 0
Now taking 4x3 + 2x2 − 8x + 7
2x(2x2 − 2x − 1) + 4x2 + 2x + 2x2 − 8x + 7
2x(2x2 − 2x − 1) + 6x2 − 6x + 7
As, 2x2 − 2x − 1 = 0
2x(0) + 3(2x2 − 2x − 1)) + 7 + 3
0 + 3(0) + 10
10
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