# Chapter 6: Algebraic Expressions and Identities Exercise – 6.3

Find products

5x× 4x3

### Solution:

To multiply algebraic expressions, we use commutative and associative laws along with the laws of indices. However, use of these laws is subject to their applicability in the given expressions. In the present problem, to perform the multiplication, we can proceed as follows:

Find products

−3a2 × 4b4

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 3

Find products

(−5xy) × (−3x2yz)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Find products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Find products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Find products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Find products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Find products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 9

Find the products

(7ab) × (− 5ab2c) × (6abc2)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 10

Find the products

(−5a) × (−10a2) × (−2a3)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 11

Find the products

(−4x2) × (−6xy2) × (−3yz2)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 12

Find the products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, am× an = an, wherever applicable.

We have:

### Question: 13

Find the products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 14

Find the products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 15

Find the products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 16

Find the products

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 17

Find the products

(2.3xy) × (0.1x) × (0.16)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

(2.3xy) × (0.1x) × (0.16)

= (2.3 × 0.1 × 0.16) × (x × x) × y

= (2.3 × 0.1 × 0.16) × (x1+1) × y

= 0.0368x2y

### Question: 18

Express the products as a monomials and verify the result for x = 1

(3x) × (4x) × (−5x)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 19

Express the products as a monomials and verify the result for x = 1

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Since, LHS = RHS for x = 1; therefore, the result is correct

Thus, the answer is – (48/5) x6.

### Question: 20

Express the products as a monomials and verify the result for x = 1

(5x4) × (x2)3 × (2x)2

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Since, LHS = RHS for x = 1; therefore, the result is correct

### Question: 21

Express the products as a monomials and verify the result for x = 1

(x2)3 × (2x) × (−4x) × (5)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Since, LHS = RHS for x = 1; therefore, the result is correct

### Question: 22

Write down the product of −8x2y6 and −20xy. Verify the product for x = 2.5, y = 1.

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Because LHS is equal to RHS, the result is correct.

### Question: 23

Evaluate (3.2x 6y3) × (2.1x2y2) when x = 1 and y = 0.5.

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 24

Find the value of (5x6) × (−1.5x2y3) × (−12xy2) when x = 1, y = 0.5.

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 25

Evaluate when (2.3a5b2) × (1.2a2b2) when a = 1 and b = 0.5.

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 26

Evaluate for (−8x2y6) × (−20xy) x = 2.5 and y = 1

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 27

Express the products as a monomials and verify the result for x = 1, y = 2

(-xy3) × (yx3) × (xy)

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 28

Express the products as a monomials and verify the result for x = 1, y = 2

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

Because LHS is equal to RHS, the result is correct.

### Question: 29

Express the products as a monomials and verify the result for x = 1, y = 2

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 30

Express the products as a monomials and verify the result for x = 1, y = 2

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 31

Express the products as a monomials and verify the result for x = 1, y = 2

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 32

Evaluate of the following when x = 2, y = -1.

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

### Question: 33

Evaluate of the following when x = 2, y = -1.

### Solution:

To multiply algebraic expressions, we can use commutative and associative laws along with the law of indices, a× an = an, wherever applicable.

We have:

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