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Chapter 20: Linear Equation in One Variable Exercise – 20.3

Question: 1

Find the area of the pentagon shown in figure below, if AD = 10 cm, AG = 8 cm, AH= 6 cm, AF= 5 cm, BF = 5 cm, CG = 7 cm and EH = 3 cm.

Chapter 20: Linear Equation in One Variable Exercise – 20.3

Solution:

Given:

AD = 10 cm, AG = 8 cm, AH = 6 cm, AF = 5 cm

BF = 5 cm, CG = 7 cm, EH = 3 cm

Therefore, FG = AG – AF = 8 – 5 = 3 cm

And, GD = AD – AG = 10 – 8 = 2 cm

From given figure:

Chapter 20: Linear Equation in One Variable Exercise – 20.3

 

Question: 2

Find the area enclosed by each of the following figures (Fig. 20.49 (i)-(iii)J as the sum of the areas of a rectangle and a trapezium:

Chapter 20: Linear Equation in One Variable Exercise – 20.3

Solution:

(i) From the figure:

Area of the complete figure = (Area of square ABCF) + (Area of trapezium CDEF)

Chapter 20: Linear Equation in One Variable Exercise – 20.3

 

Question: 3

There is a pentagonally shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.

Chapter 20: Linear Equation in One Variable Exercise – 20.3

Find the area of this park using both ways. Can you suggest some another way of finding its area?

Solution:

A pentagonal park is given below:

Chapter 20: Linear Equation in One Variable Exercise – 20.3

Jyoti and Kavita divided it in two different ways.

(i) Jyoti divided is into two trapeziums. It is clear that the park is divided in two equal trapeziums whose parallel sides are 30 m and 15 m.

Chapter 20: Linear Equation in One Variable Exercise – 20.3

 

Question: 4

Find the area of the following polygon, if AL =10 cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.

Chapter 20: Linear Equation in One Variable Exercise – 20.3

Solution:

Given: AL = 10 cm, AM=20 cm, AN=50 cm

AO = 60 cm, AD = 90 cm

Hence, we have the following: MO = AO – AM = 60 – 20 = 40 cm

OD = AD – A0 = 90 – 60 = 30 cm

ND = AD – AN = 90 – 50 = 40 cm

LN = AN – AL = 50 – 10 = 40 cm

From given figure:

Area of Polygon = (Area of triangle AMF) + (Area of trapezium MOEF) + (Area of triangle DNC) + (Area of trapezium NLBC) + (Area of triangle ALB)

Chapter 20: Linear Equation in One Variable Exercise – 20.3

 

Question: 5

Find the area of the following regular hexagon.

Chapter 20: Linear Equation in One Variable Exercise – 20.3

Solution:

The given figure is :

Join QN

Chapter 20: Linear Equation in One Variable Exercise – 20.3

It is given that the hexagon is regular. So, all its sides must be equal to 13 cm.

Also, AN = BQ

QB + BA + AN = QN

AN + 13 + AN = 23

2AN = 23 – 13 = 10

Chapter 20: Linear Equation in One Variable Exercise – 20.3


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