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```Chapter 9: Ratio, Proportion and Unitary Method Exercise 9.2

Ratio, Proportion and Unitary Method – Exercise 9.2 – Q.1

(i) 3 : 4 (or) 9 : 16

Writing the given ratios as fractions, we have Now L.C.M of 4 and is is 16

Making the denominaator of each fraction

equal to 16, we have Clearly 12 >9 (ii) 15 : 16 or 24 : 24

Writing the given ratio as fractions, we have L.C.M of 25 & 16 is = 400

Making the denominator of each fraction equal to 400, we have clearly 384 > 375 (iii) 4 :7 or 5 : 8 Now, LCM of 7 and 8 is 56. Clearly 35 > 32 (iv) 9 : 20 or 8 : 13. Now, LCM of 20 and 13 is 260 Clearly 160 > 117 (v) 1 : 2 or 13 : 27 Now, LCM of 2 and 27 is 54 Ratio, Proportion and Unitary Method – Exercise 9.2 – Q.2

i.e. have. ∴  3 : 4 is an equivalent ratio of 6 : 15 So, 12 : 16 is an equivalent ratios of 6:8. Hence, 3 : 4 and 12 : 16 are equivalent ratios of 6 : 8.

Ratio, Proportion and Unitary Method – Exercise 9.2 – Q.3 In order to find the first missing number, we consider the denominator 20 and 35

LCM of 20 and 5 is 20.

We have 20 ÷ 4 = 4.

So, we divide the Nr or of 12/20 by 4 to get Hence, first missing number is 3, consequently the second ratio is 3/5

To find the second missing number, we consider We have 9 ÷ 3 = 3, so we multiply the nr ∆ or of 3/5 by 3 to get Hence, the second missing number is 15.
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