×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details

# Chapter 5: Trigonometric Functions – Exercise 5.2

## Trigonometric Functions – Exercise 5.2 – Q.1

we have,

cosec2θ - cot2θ = 1

⟹ cosec2 θ = 1 + cot2 θ

In the third quadrant cosec θ is negative

We have,

sin2θ + cos2θ = 1

⟹ sin2θ = 1 - cos2θ

In the 2nd quadrant sin θ is positive and tan θ is negative

In the third quadrant cosec θ is negative

We have,

sin2θ + cos2 θ = 1

⟹ cos2 θ = 1 - sin2 θ

In the 1st quadrant cos θ is positive and tan θ is also positive

## Trigonometric Functions – Exercise 5.2 – Q.2

We have,

sin2θ + cos2θ = 1

⟹ cos2θ = 1 - sin2θ

In the 2st quadrant cos θ is negative and tan θ is also negative

## Trigonometric Functions – Exercise 5.2 – Q.3

We have,

⟹ θ lies in the second quadrant and Φ lies in the third quadrant.

Now, sin2 θ + cos2 θ = 1

⟹ cos2 θ = 1 - sin2 θ

In the 2st quadrant cos θ is negative and tan θ is also negative

In the third quadrant sec Φ is negative

### Course Features

• 728 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution