R.D. Sharma Solutions Class 11 | Math Chapter 4 Measurement of Angles Exercise 4.1

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Chapter 4: Measurement of Angles – Exercise 4.1

Measurement of Angles – Exercise 4.1 – Q.1

(i)   9π/5

We have,

π radians = 180°



Now,



= 324°

(ii)   (-5π)/6

We have,

π radians = 180°



Now,



(iii)  (18π/5)^c

We have

π radians = 180°



Now,



(iv) We have,



Now,



(v) We have,

π radians = 180°



Now,



= 630°

(vi) We have,

π radians = 180°



Now,



 

Measurement of Angles – Exercise 4.1 – Q.2

(i) 300°

We have, 180° = π^c



Now,



(ii) 35°

We have,

180° = π^c



Now,



(iii) – 56°

We have

180° = π^c



Now,



(iv) 135°

We have,

180° = π^c



Now,



(v)  – 300°

We have

180° = π^c



Now,



(vi) 7°30¹

We have,

180° = π^c



(vii) 125°30¹

We  have

180° = π^c



(viii)  – 47°30¹

we have,

180° = π^c



 

Measurement of Angles – Exercise 4.1 – Q.3

Let θ₁ and θ₂ be two acute angles of a right angled triangle.

∴ difference of acute angles



∵  in a right angled triangle,



On solving



From equation (ii)



So angles in degrees



 

Measurement of Angles – Exercise 4.1 – Q.4

Let θ₁ and θ₂ and θ₃ be the angle or triangle.



Now,

We have to express all the angles in degrees



By angle slam property,



⟹ x = 40^°

∴  θ₁ = 24^°, θ₂ = 60^°, θ₃ = 96^°