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We have,
and,
σ = 5.1
⟹ σ2 = 26.01
When the incorrect observation 50 is replaced by 40:
we have, Incorrect Σxi = 4000
∴Corrected Σxi = 4000 - 50 + 40 = 3990
Converting the given data into continuous frequency distribution by subtracing 0.5 from the lower limit and adding 0.5 to the upper limit of each dass interval.
Mean = 40
SD = 10
n = 100
Σxi = 40 × 100 = 4000
Corrected Sum = 4000 - 30 - 70 + 3 + 27 = 3930
Variance = 100
Mean = 45
Variance = 16
n = 10
Σxi = 450
Corrected Sum = 450 - 52 + 25 = 423
Corrected Mean = 42.3
Corrected Variance = 6.62*6.62 = 43.82
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