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Chapter 32: Statistics – Exercise 32.3 Statistics – Exercise – 32.3 – Q.1 We have to calculate mean deviation from the median. So, first we calculate the median.
We have to calculate mean deviation from the median. So, first we calculate the median.
Find the mean deviation from the mean for the data:
We have N = 96 ⟹ N/2 = 48
The cumulative frequency just greater than N/2 is 59 and the corresponding value of x is 38.25.
Hence, median = 38.25
M.D from Median
M.D from mean
Converting the given data into continuous frequency distribution by sub tracing 0.5 from the lower limit and adding 0.5 to the upper limit of each class interval.
Clearly, N = 100 ⟹ N/2 = 50.
Cumulative frequency is just greater than N/2 is 63 and the corresponding class is 35.5 - 40.5.
I = 35.5, f = 26, h = 5, F = 37
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Chapter 32: Statistics – Exercise 32.6...
Chapter 32: Statistics – Exercise 32.7...
Chapter 32: Statistics – Exercise 32.4...
Chapter 32: Statistics – Exercise 32.5...
Chapter 32: Statistics – Exercise 32.2...
Chapter 32: Statistics – Exercise 32.1...