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Chapter 7: Statistics Exercise – 7.2 Question: 1 The number of telephone calls received at an exchange per interval for 250 successive one- minute intervals are given in the following frequency table:
The number of telephone calls received at an exchange per interval for 250 successive one- minute intervals are given in the following frequency table:
Compute the mean number of calls per interval.
Let be assumed mean (A) = 3
Mean number of cells = 3 + 135/250 = 885/250 = 3.54
Five coins were simultaneously tossed 1000 times, and at each toss the number of heads was observed. The number of tosses during which 0, 1, 2, 3, 4 and 5 heads were obtained are shown in the table below. Find the mean number of heads per toss.
Let the assumed mean (A) = 2
Mean number of per toss = 2 + 470/1000 = 2 + 0.47 = 2.47
The following table gives the number of branches and number of plants in the garden of a school.
Calculate the average number of branches per plant.
Let the assumed mean (A) = 4
Average number of branches per plant = 4 + (-77/200) = 4 -77/200 = (800 -77)/200 = 3.615
The following table gives the number of children of 150 families in a village
Find the average number of children per family.
Solution:
Average number of children for family = 2 + 52/150 = (300 +52)/150 = 352/150 = 2.35 (approx)
The marks obtained out of 50, by 102 students in a physics test are given in the frequency table below:
Find the average number of marks.
The number of students absent in a class was recorded every day for 120 days and the information is given in the following
Find the mean number of students absent per day.
Let mean assumed mean (A) = 3
Mean number of students absent per day = 3 + 63/120 = (360 + 63)/120 = 423/120 = 3.53
In the first proof of reading of a book containing 300 pages the following distribution of misprints was obtained:
Find the average number of misprints per page.
Average number of misprints per day = 2 + (- 381/300) = (600-381)/300 = 219/300 = 0.73
Find the mean from the following frequency distribution of marks at a test in statistics:
Find the average number of accidents per worker.
Average no of accidents per day workers ⟹ x + (-187/160) = 133/160 = 0.83
Let the assumed mean (A) = 25
Mean = 25 + (-1170)/400
= 22.075
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Chapter 7: Statistics Exercise – 7.1...
Chapter 7: Statistics Exercise – 7.4...
Chapter 7: Statistics Exercise – 7.3...
Chapter 7: Statistics Exercise – 7.5...
Chapter 7: Statistics Exercise – 7.6...