Chapter 1: Real Numbers Exercise – 1.6
Question: 1
Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion.
(i) 23/8
(ii) 125/441
(iii) 35/50
(iv) 77/210

Solution:
(i) The given number is 23/8
Here, 8 = 23 and 2 is not a factor of 23.
So, the given number is in its simplest form.
Now, 8 = 23 is of the form 2m × 5n, where m = 3 and n = 0.
So, the given number has a terminating decimal expansion.
(ii) The given number is 125/441
Here, 441 = 32 × 72 and none of 3 and 7 is a factor of 125.
So, the given number is in its simplest form.
Now, 441 = 32 × 72 is not of the form 2m × 5n
So, the given number has a non-terminating repeating decimal expansion.
(iii) The given number is 35/50 and HCF (35, 50) = 5.

Here, 7/10 is in its simplest form.
Now, 10 = 2 × 5 is of the form 2m × 5n, where in = 1 and n = 1.
So, the given number has a terminating decimal expansion.
(iv) The given number is 77/210 and HCF (77, 210) = 7.

Here, 11/30 is in its simplest form. 30
Now, 30 = 2 × 3 × 5 is not of the form 2m × 5n.
So, the given number has a non-terminating repeating decimal expansion.
(v) The given number is
Clearly, none of 2, 5 and 7 is a factor of 129.
So, the given number is in its simplest form.
Question: 2
Write down the decimal expansions of the following rational numbers by writing their denominators in the form of 2m × 5n, where m, and n, are the non- negative integers.
(i) 3/8
(ii) 13/125
(iii) 7/80
(iv) 14588/625

Solution:
(i) The given number is 3/8
Clearly, 8 = 23 is of the form 2m × 5n, where m = 3 and n = 0.
So, the given number has terminating decimal expansion.

(ii) The given number is 13/125
Clearly, 125 = 53 is of the form 2m × 5″, where m = 0 and n = 3.
So, the given number has terminating decimal expansion.

(iii) The given number is 7/80.
Clearly, 80 = 24 × 5 is of the form 2m × 5n, where m = 4 and n = 1.
So, the given number has terminating decimal expansion.

(iv) The given number is 14588/625
Clearly, 625 = 54 is of the form 2m × 5n, where m = 0 and n = 4.
So, the given number has terminating decimal expansion?

(v) The given number is
Clearly, 22 × 57 is of the form 2m × 5n, where in = 2 and n = 7.
So, the given number has terminating decimal expansion?

Question: 3
What can you say about the prime factorization of the denominators of the following rational?
(i) 43.123456789

(iv) 0.120120012000120000
Solution:
(i) Since 43.123456789 has terminating decimal expansion. So, its denominator is of the form 2m × 5n, where m, n are non-negative integers.
(ii) Since
has non-terminating decimal expansion. So, its denominator has factors other than 2 or 5.
(iii) Since
has non-terminating decimal expansion. So, its denominator has factors other than 2 or 5.
(iv) Since 0.120120012000120000 … has non-terminating decimal expansion. So, its denominator has factors other than 2 or 5.
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