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x – 3 = 5
Adding 3 to both sides, we get
x – 3 + 3 = 5 + 3
x = 8
Verification:
Substituting x = 8 in LHS, we get
LHS = x – 3 and RHS = 5
LHS = 8 – 3 = 5 and RHS = 5
LHS = RHS
Hence, verified.
x + 9 = 13
Subtracting 9 from both sides, we get
=> x + 9 – 9 = 13 – 9
=> x = 4
Substituting x = 4 on LHS, we get
LHS = 4 + 9 = 13 = RHS
3x = 0
Dividing both sides by 3, we get
3x/3 = 0/3
x = 0
Substituting x = 0 in LHS = 3x, we get LHS = 3 × 0 = 0 and RHS = 0
x/2 = 0
Multiplying both sides by 2, we get
=> (x/2) × 2 = 0 × 2
=> x = 0
Substituting x = 0 in LHS, we get
LHS = 0/2 = 0 and RHS = 0
LHS = 0 and RHS = 0
10 – y = 6
Subtracting 10 from both sides, we get
10 – y – 10 = 6 – 10
-y = -4
Multiplying both sides by -1, we get
-y × -1 = - 4 × - 1
y = 4
Substituting y = 4 in LHS, we get
LHS = 10 – y = 10 – 4 = 6 and RHS = 6
7 + 4y = - 5
7 + 4y = -5
Subtracting 7 from both sides, we get
7 + 4y – 7 = -5 -7
4y = -12
Dividing both sides by 4, we get
y = -12/ 4
y = -3
Substituting y = -3 in LHS, we get
LHS = 7 + 4y = 7 + 4(-3) = 7 – 12 = -5, and RHS = -5
Adding 8 to both sides, we get
3(x + 2) = 15
3 (x + 2) = 15
(x + 2) = 5
Subtracting 2 from both sides, we get
x + 2 – 2 = 5 – 2
x = 3
Substituting x = 3 in LHS, we get
LHS = 3 (x + 2) = 3 (3 + 2) = 3(5) = 15, and RHS = 15
x/4 = 7/8
Multiplying both sides by 4, we get
1/3 - 2x = 0
Subtracting 13 from both sides, we get
3(x + 6) = 24
(x + 6) = 8
Subtracting 6 from both sides, we get
x + 6 – 6 = 8 – 6
x = 2
Substituting x = 2 in LHS, we get
LHS = 3(x + 6) = 3(2 + 6) = 24, and RHS = 24
3(x + 2) - 2(x – 1) = 7
3(x + 2) – 2(x – 1) = 7
On expanding the brackets, we get
3× x + 3 × 2 – 2 × x + 2 × 1 = 7
3x + 6 – 2x + 2 = 7
3x – 2x + 6 + 2 = 7
x + 8 = 7
Subtracting 8 from both sides, we get
x + 8 – 8 = 7 – 8
x = -1
Substituting x = -1 in LHS, we get
LHS = 3 (x + 2) -2(x -1) = 3 (-1 + 2) -2(-1-1) = (3×1) – (2×-2) = 3 + 4 = 7, and RHS = 7
8(2x – 5) - 6(3x – 7) = 1
8(2x – 5) – 6(3x – 7) = 1
On expanding the brackets, we get (8 × 2x) – (8 × 5) – (6 × 3x) + (-6) × (-7) = 1
16x – 40 – 18x + 42 = 1
16x – 18x + 42 – 40 = 1
-2x + 2 = 1
-2x+ 2 – 2 = 1 -2
-2x = -1
-2x × (-1) = -1× (-1)
2x = 1
Dividing both sides by 2, we get
Substituting x = 1/2 in LHS, we get
= 8(1 – 5) – 6(32 – 7)
= 8× (-4) – (6 × 32) + (6 × 7) = -32 – 9 + 42 = – 41 + 42 = 1= RHS
6(1 – 4x) + 7(2 + 5x) = 53
On expanding the brackets, we get (6 ×1) – (6 × 4x) + (7 × 2) + (7 × 5x) = 53
6 – 24x + 14 + 35x = 53
6 + 14 + 35x – 24x = 53
20 + 11x = 53
Subtracting 20 from both sides, we get 20 + 11x – 20 = 53 – 20
11x = 33
Dividing both sides by 11, we get
11x/11 = 33/11
= 6(1 – 4 × 3) + 7(2 + 5 × 3)
= 6(1 – 12) + 7(2 + 15)
= 6(-11) + 7(17)
= - 66 + 119
= 53 = RHS
5(2 – 3x) - 17(2x – 5) = 16
5(2 – 3x) -17(2x – 5) = 16
On expanding the brackets, we get (5 × 2) – (5 × 3x) – (17 × 2x) + (17 × 5) = 16
10 – 15x – 34x + 85 = 16
10 + 85 – 34x – 15x = 16
95 – 49x = 16
Subtracting 95 from both sides, we get – 49x + 95 – 95 = 16 – 95
-49x = -79
Dividing both sides by – 49, we get
Adding 2 to both sides, we get
5(x – 2) +3(x + 1) = 25
5(x – 2) + 3(x + 1) = 25
(5 × x) – (5 × 2) +3× x + 3× 1 = 25
5x – 10 + 3x + 3 = 25
5x + 3x – 10 + 3 = 25
8x – 7 = 25
Adding 7 to both sides, we get
8x – 7 + 7 = 25 + 7
8x = 32
Dividing both sides by 8, we get
8x/8 = 32/8
x = 4
Verification :
Substituting x = 4 in LHS, we get
= 5(4 – 2) + 3(4 + 1) = 5(2) + 3(5) = 10 + 15 = 25 = RHS
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Chapter 8: Linear Equations in One Variable...