Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Illustration:
Find the 4th and 8th term of the series 6, 4, 3, ……
Solution:
Consider1/6, /14, 1/3, ...... ∞
Here T2 – T1 = T3 – T2 = 1/12 ⇒ 1/6, 1/4, 1/3 is an A.P.
4th term of this A.P. = 1/6 + 3 × 1/12 = 1/6 + 1/4 = 5/12,
And the 8th term = 1/6 + 7 × 1/12 = 9/12.
Hence the 8th term of the H.P. = 12/9 = 4/3 and the 4th term = 12/5.
If a, b, c are in H.P., show that a/b+c, b/c+a, c/a+b are also in H.P.
Given that a, b, c are in H.P.
⇒ 1/a, 1/b, 1/c are in A.P.
⇒ a+b+c/a, a+b+c/b, a+b+c/c are in A.P.
⇒ 1 + b+c/a, 1 + c+a/b, 1 + a+b/c are in A.P.
⇒ b+c/a, c+a/b, a+b/c are in A.P.
⇒ a/b+c, b/c+a, c/a+b are in H.P.
Some Important Results
• 1 + 2 + 3 +…+ n = n/2(n + 1) (sum of first n natural numbers).
• 12 + 22 + 32 +…+ n2 = n(n+1)(2n+1)/6 (sum of the squares of first n natural numbers).
• 13 + 23 + 33 +…+ n3 = n2(n+1)2/4 = (1 + 2 + 3 +…+ n)2 (sum of the cubes of first n natural numbers).
• (1 – x)–1 = 1 + x + x2 + x3 +… –1 < x < 1.
• (1 – x)–2 = 1 + 2x + 3x2 +… –1 < x < 1.
Find the nth term and the sum of n terms of the series 1.2.4 + 2.3.5 + 3.4.6 +…
rth term of the series = r(r+1).(r+3)=r3 + 4r2 + 3r
So sum of n terms = Σnr=1 r3 + 4Σnr=1 r2 + 3Σnr=1 r
= (n(n+1)/2)2 + 4 n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)/12 {3n2 + 19n + 26}.
Find the sum of the series 1.n + 2(n–1) + 3.(n–2) +…+ n.1.
The rth term of the series is
tr = (1 + (r – 1).1)(n + (r–1)(–1))
= r(n – r + 1) = r(n + 1) – r2
⇒ Sn= Σnr=1 tr Σnr=1 (n+1)r – Σnr=1 r2 = (n+1) n.(n+1)/2 – n(n+1)(2n+1)/6
= n.(n+1)/2 [n + 1 – 2n+1/3] = n(n+1)(n–2)/6.
To read more, Buy study materials of Sequences and Series comprising study notes, revision notes, video lectures, previous year solved questions etc. Also browse for more study materials on Mathematics here.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Harmonic Mean Table of Content Formula for...
IIT JEE Examples Based on Relationship between AM,...
IIT JEE Arithmetic Mean between two numbers | JEE...
Geometric Progression (G.P.) Table of contents...
Relationship between A.M. and G.M. Table of...
IIT JEE Arithmetic Progression | JEE Progression...
IIT JEE Sum of First N Terms Of AP | JEE The Sum...
IIT JEE Arithmetic Mean Examples | JEE Arithmetic...
Weighted Means Let a 1 , a 2 , ……, a...
IIT JEE Basic Principle of AP | JEE Principle of...
Solved Examples based on GP Solved examples :...
Sum to n terms of Special Series Table of contents...
Sequences Table of contents Meaning of Sequence...
Geometric Progression Geometric Progression as the...
Method of Differences Suppose a 1 , a 2 , a 3 ,...
Download IIT JEE Solved Examples Based on...
IIT JEE Basic Concepts of Sequences and Pattern |...
Relation between A.M., G.M. and H.M. Let there are...
Introduction of Sequences and Series Table of...
Harmonic Progression Harmonic progression is an...
Arithmeticogeometric Progression Solved Examples...
IIT JEE Arithmetic Geometric Progression | JEE...
IIT JEE Geometric Mean | JEE Geometric Mean of A...
Arithmetic Mean of mth Power The concept of...
Series Table of contents Meaning of Series History...