Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
21: Area bounded by y = g(x), x-axis and the lines x = -2, x = 3, where
and f(x) = x2 - , is equal to
(A) 113/24 sq.units (B) 111/24 sq.units
(C) 117/24 sq.units (D) 121/24 sq,units
22: Area of the region which consists of all the points satisfying the conditions |x–y| + |x+y| < 8 and xy > 2, is equal to
(A) 4(7 – ln8)sq. units (B) 4(9 – ln8)sq. units
(C) 2(7 – ln8)sq. units (D) 2(9 – ln8)sq. units
Solution: The expression |x–y| + |x+y| < 8, represents the interior region of the square formed by the lines x = ± 4, y = ± 4 and xy > 2. represents the region lying inside the hyperbola xy =2
Required area
= 4(7–3 In2) sq.units
= 4(7 – In8) sq.units
23: Area bounded by the parabola (y - 2)2 = x – 1, the tangent to it at the point P (2, 3) and the x-axis is equal to
(A) 9 sq. units (B) 6 sq. units
(C) 3 sq. units (D) None of these
Solution: (y - 2)2 = (x - 1) => 2(y - 2). = 1
=> dy/dx = 1/2(y–2)
Thus equation of tangent at P(2, 3) is,
(y – 3) = 1/2 (x–2) i.e., x = 2y – 4
= ((y–2)3/3 – y2 + 5y)30 = 9 sq. units
24: Two lines draw through the point P(4, 0) divide the area bounded by the curves y = √2 πx/4 and x – axis, between the linea x = 2, and x = 4, in to three equal parts. Sum of the slopes of the drawn lines is equal to
(A) –2 2/π (B) –√2/π
(C) –√2/π (D) –4√2/π
Solution: Area bounded by y = √2 .sin πx/4 and x-axis between the lines x = 2 and x = 4,
Let the drawn lines are L1: y – m1(x - 4) = 0 and L2: y – m2(x - 4) = 0, meeting the line x = 2 at the points A and B respectively Clearly A = (2, - 2m1); B= (2, -2m2)
25: If A = is equal to
(A) 1/π+2 – A (B) 1/2 + 1/π+2 – A
(C) 1/2 – 1/π+2 – A (D) 1/2 + 1/π+2 + A
26. The value of the integral is
(A) 1 (B) π/12
(C) π/6 (D) none of these
Solution: Using the property f (a + b – x) dx, the given integral
Hence (B) is the correct answer.
27. If I = dx then
(A) 0 (B) 2
(C) π/2 (D) 2 – π/2
Hence (D) is the correct answer.
28. If I = , then
(A) 0 < I < 1 (B) I > π/2
(C) I < √2π (D) I > 2 π
Solution: Since x ∈ [0, π/2] => 1 < 1 + sin3 x < 2
Hence (C) is the correct answer.
29. If f (a + b –x) = f (x) then ∫ba x f (x) dx is equal to
(A) a–b/2 ∫ba f(x) dx (B) (a+b/2) ∫ba f(x) d x
(C) 0 (D) none of these
Solution: I = ∫ba x f (x) dx = ∫ba (a+b-x) f (a +b-x) dx
= (a + b) ∫ba f(a +b –x) - ∫ba x f (a + b –x) dx
= ( a + b) ∫ba f (x) dx - ∫ba x f (x) d x
Hence I = (a+b/2) ∫ba f(x) dx.
To read more, Buy study materials of Definite integral comprising study notes, revision notes, video lectures, previous year solved questions etc. Also browse for more study materials on Mathematics here.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Definite Integration Geometrical Interpretation of...
Definite Integral as Limit of a Sum Table of...
Properties of Definite Integration Definite...
Area as Definite Integral Table of Content...
Solved Examples of Definite Integral Solved...
Solved Examples of Definite Integral Part I 11:...
Working Rule for finding the Area (i) If curve...
Objective Problems of Definite Problems Objective...