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Continue Shopping ```Operations on Determinants

Multiplication of two Determinants Two determinants can be multiplied together only if they are of same order. The rule of multiplication is as under:

Take the first row of determinant and multiply it successively with 1st, 2nd & 3rd rows of other determinant. The three expressions thus obtained will be elements of 1st row of resultant determinant. In a similar manner the element of 2nd & 3rd rows of determinant are obtained. where, R1 → first row of first determinant

Ri  → first row of second determinant

Illustration:

Find the product of the determinants Solution:

= Differentiation of a Determinant

Yes, let f(x) = be a given function.

=> f(x) = a(x) d(x) - c(x) b(x)

=> f'(x) = a'(x) d(x) + a(x) d'(x) - c'(x) b(x) - c(x) b'(x)

=> a'(x) d(x) - c'(x) b(x) + a(x) d'(x) - c(x) b'(x)

= Thus, the differential coefficient of a determinant is obtained by differentiating a single row (or column) at a time and finally adding the determinants so obtained.

Thus, for a determinant of order 'n'. Summation of Determinants

Let Δr= , where a,b,c,l,m and n are constants independents of r,

then  =∑nr=1  ?r = Here functions of r can be the elements of only one row or column. None of the elements other of than that row or column should be dependent on r.

Illustration:

Let Δa= . Showthat ∑na=1 ?a = 0

Solution:

By adding all the corresponding elements of C1 of all determinants Δa we have By taking (n-1)n/2 as common factor from C1 and 6 as common factor from C3, we get Since C1 and C3 are identical ∑na=1  ?a =0.

Special Determinants

1. Symmetric determinant

The elements situated at equal distance from the diagonal are equal both in magnitude and sign. = abc + 2fgh - af2 - bg2 - ch2.

2. Skew symmetric determinant

All the diagonal elements are zero and the elements situated at equal distance form the diagonal are equal in magnitude but opposite in sign. The value of a skew symmetric determinant of odd order is zero. = 0.

3. Circulant determinant:

The elements of the rows (or columns) are in cyclic arrangement. = -(a3 + b3 + c3 - 3abc).

4. = (a-b)(b-c)(c-a).

5. = (a-b)(b-c)(c-a)(a+b+c).

6. = (a-b)(b-c)(c-a)(ab+bc+ca).

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