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Grade 11Mechanics

A block of mass 2 kg slides down an incline plane of inclination 30°. The coefficient of friction between block and plane is 0.5. The contact force between block and plank is :

Profile image of chintan
10 Years agoGrade 11
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1 Answer

Profile image of Neeti
10 Years ago
Contact force is the resultant of Frictional force and normal reaction force. 
The frictional force can be calculated as = 0.5 x mgcos theta. = 0.5 x 2 x 10 x root 3 / 2
normal reaction force is Mgcos theta. = 2 x 10 x root 3 / 2 
 
They are at 90 degrees to each other therefore find out their resultant and that shall be the resultant contact force.
 
I hope this helps :) Please approve the answer if you think it’s useful :)