[email protected]
India's First Online IIT-JEE & NEET Coaching Platform - Trusted Since 2006
+91-87964 74404
Question icon
Grade 12Mechanics

man can swim with a v relative 2 water.he has 2 cross a river of width d flowing with a velocity u man can swim with a v relative 2 water.he has 2 cross a river of width d flowing with a velocity v.v is greater then u distance through whch it is carried downstream by the river is x..................what is the angle the swimmer makes with river flow for x 2 be minimum

Profile image of jauneet  singh
16 Years agoGrade 12
Answers icon

1 Answer

Profile image of Askiitians Tutor Team

Askiitians Tutor Team

ApprovedApproved Tutor Answer1 Year ago

To determine the angle at which a swimmer should swim to minimize the downstream distance traveled while crossing a river, we need to analyze the situation using some basic principles of physics and vector analysis. Let's break it down step by step.

Understanding the Scenario

We have a river flowing with a velocity \( u \) and a swimmer who can swim with a velocity \( v \) relative to the water. The swimmer needs to cross a river of width \( d \). The goal is to find the angle \( \theta \) that the swimmer should make with the flow of the river to minimize the downstream distance \( x \) that he is carried while crossing.

Setting Up the Problem

When the swimmer swims at an angle \( \theta \) relative to the flow of the river, we can break down his swimming velocity into two components:

  • The component across the river (perpendicular to the flow): \( v \sin(\theta) \)
  • The component downstream (parallel to the flow): \( v \cos(\theta) \)

Time to Cross the River

The time \( t \) it takes for the swimmer to cross the river can be calculated using the width \( d \) and the perpendicular component of his swimming velocity:

\( t = \frac{d}{v \sin(\theta)} \)

Downstream Distance Traveled

During this time, the river carries the swimmer downstream. The total downstream distance \( x \) can be expressed as:

\( x = u \cdot t = u \cdot \frac{d}{v \sin(\theta)} \)

Minimizing the Downstream Distance

To minimize \( x \), we need to minimize the expression:

\( x = \frac{ud}{v \sin(\theta)} \)

To find the optimal angle \( \theta \), we can take the derivative of \( x \) with respect to \( \theta \) and set it to zero. However, a more intuitive approach is to consider the relationship between the velocities.

Finding the Optimal Angle

To minimize \( x \), the swimmer should aim to swim in such a way that the component of his swimming velocity directly counters the river's flow. This leads us to the condition:

\( v \cos(\theta) = u \)

From this, we can derive:

\( \cos(\theta) = \frac{u}{v} \)

Thus, the angle \( \theta \) can be found using:

\( \theta = \cos^{-1}\left(\frac{u}{v}\right) \)

Conclusion

By swimming at this angle, the swimmer effectively minimizes the downstream distance \( x \) while crossing the river. This approach ensures that the swimmer's velocity is optimally directed to counteract the river's current, allowing for the most efficient crossing. Remember, this analysis assumes that the swimmer's speed \( v \) is greater than the river's speed \( u \), which is crucial for this strategy to work.